Saturday, February 4, 2012

Practice Test for Reaction Rate Unit - Solutions

Below are scans of the practice quiz given out in class on Thursday. Unfortunately, I cannot upload the pdf of the practice exam like I said in an earlier post. If you did not get a copy of the practice exam, you will just have to use the images below. Also, an explanation to problem #19 is below. Also, the practice exam did not cover any nuclear material from the Chapter 21 work packet. There will be questions pertaining to nuclear chemistry on Monday's exam.

  • Problem #19 could be solved with a calculation using the equation to find activation energy (Arrenius Equation - don't worry about the name). A simpler way (and the expected way) is to notice the trend of increase in temperature and rate constants. The increase in temperature of 20 Kelvin (273 K to 293 K) had a rate constant "k" increase of 0.046 to 0.081. A roughly 20 Kelvin increase in temperature (293 K to 310 K) should also cause another 0.04X increase in the rate constant. Therefore, 0.081 + 0.04 = 0.12.

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